SPM 2024 Add Maths Paper 2, Question 14Kinematics of Linear Motion
Solved on video in English and Bahasa Melayu · 4 marks · Form 5, Kinematics of Linear Motion · 6:45 video
The question
Solution by graph sketching is not accepted.
Particle P moves along a straight line such that fixed points A and B lie on the straight line. Its velocity, in m s⁻¹, is given by v = 3t² + 4t − 15, such that t is the time, in seconds, after passing through point A towards point B.
[Assume motion to the right is positive.]
(a) Determine whether point A is to the left or to the right of point B. Justify your answer.
Determine whether point A is to the left or to the right of point B. Justify your answer.
(b) Find the acceleration, in m s⁻², of the particle at t = 1.3 s.
Find the acceleration, in m s⁻², of the particle at t = 1.3 s.
(c) If the distance between points A and B is 15 m, determine whether the particle will pass point B or not. Give a reason for your answer. [4 marks]
If the distance between points A and B is 15 m, determine whether the particle will pass point B or not. Give a reason for your answer. [4 marks]
[4 marks]
(d) Particle Q moves along the same straight line such that its velocity, v m s⁻¹, is given by v = 2t² − 7t + 6, such that t is the time, in seconds, after passing through point A.
Determine the range of time, in seconds, when both particles move to the left.
Particle Q moves along the same straight line such that its velocity, v m s⁻¹, is given by v = 2t² − 7t + 6, such that t is the time, in seconds, after passing through point A.
Determine the range of time, in seconds, when both particles move to the left.
Part (a)
Step 1
Substitute t = 0 (at point A) into the velocity function: v = 3(0)² + 4(0) − 15 = −15 m s⁻¹.
Why this step
t is counted from passing A, so t = 0 is exactly at A. Its velocity there shows which way P sets off towards B.
4 more steps, each with the reason for it, in the full solution
Final answer
A is to the right of B
Where students lose marks
Watch out: v < 0 means the particle heads left towards B, so B is left of A, not the other way round.
Part (b)
3 more steps, each with the reason for it, in the full solution
Final answer
a = 11.8 m s⁻²
Where students lose marks
Watch out: differentiate carefully, 3t² becomes 6t (not 5t), then substitute t = 1.3.
Part (c)
10 more steps, each with the reason for it, in the full solution
Final answer
No, P does not pass B (400/27 m < 15 m)
Where students lose marks
Watch out: finding −400/27 m is not enough. Compare its size with 15 m and state clearly that P does not reach B.
Part (d)
8 more steps, each with the reason for it, in the full solution
Final answer
3/2 < t < 5/3
Where students lose marks
Watch out: 'both' means the overlap of the two time ranges. Draw a number line and keep only the part shaded by both.
Watch every step of this question solved on video (6:45), with the reason behind each step and a box that checks your own answer.
No card. Every past-year question on video, in English and BM.
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