SPM 2020 Add Maths Paper 2, Question 12Kinematics of Linear Motion
Solved on video in English and Bahasa Melayu · Form 5, Kinematics of Linear Motion · 6:10 video
The question
(Solution by graph sketching is NOT accepted.) Diagram 6 shows particle P and particle Q moving along a straight line through a fixed point O, with A----21 m----O----33 m----B (P starts at A, Q starts at B). Particle P starts moving from A and particle Q starts moving from B simultaneously. After t seconds, the velocity (v ms⁻¹ of P is vP = 2t - 4 and of Q is vQ = 8 - 2t. (a) Determine which particle passes through the fixed point O first. Hence, state the time, in seconds.
(b) The two particles meet after k seconds. Find the value of k.
(c) Find the furthest distance, in m, between particle P and particle Q during the motion.
6:10Part (a)
Step 1
Displacement (measured from each particle's start, taking A as origin for both): integrate velocity.
Why this step
Velocity only tells us how fast position changes. To get position we integrate, and skipping this is where weaker candidates lose marks.
5 more steps, each with the reason for it, in the full solution
Final answer
P passes O first, at t = 7 s
Where students lose marks
Watch out: measure both positions from A, so Q's constant is 54, not 0. Then clearly state the time, t = 7 s.
Part (b)
5 more steps, each with the reason for it, in the full solution
Final answer
k = 9
Where students lose marks
Watch out: 'meet' means equal positions (sP = sQ), not equal velocities. Setting vP = vQ finds a different moment.
Part (c)
5 more steps, each with the reason for it, in the full solution
Final answer
72 m
Where students lose marks
Watch out: use one gap g(t) = sQ − sP at a single time. Adding each particle's turning-point distance (74 m) mixes different times.
Watch every step of this question solved on video (6:10), with the reason behind each step and a box that checks your own answer.
No card. Every past-year question on video, in English and BM.
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