SPM 2021 Add Maths Paper 2, Question 12Kinematics of Linear Motion
Solved on video in English and Bahasa Melayu · Form 5, Kinematics of Linear Motion · 6:59 video
The question
Solution by graph sketching is not accepted. Two particles, A and B, move along a straight line. The velocity of particle A, v_A m s⁻¹, is given by v_A = 24t − 4t² − 20, while the velocity of particle B, v_B m s⁻¹, is given by v_B = 24t − 25, where t is the time, in seconds, after both particles pass the fixed point O. (a) Calculate the maximum velocity, in m s⁻¹, of particle A.
Particles A and B move along a straight line with v_A = 24t − 4t² − 20 and v_B = 24t − 25, where t is the time in seconds after both pass fixed point O. (b)(i) Find the time, in seconds, when particle A and particle B meet. (b)(ii) Find the total distance, in m, travelled by particle A in the first 5 seconds.
6:59Part (a)
Step 1
Maximum velocity of A occurs when acceleration a_A = dv_A/dt = 0.
Why this step
Velocity peaks where its slope is flat. The slope of velocity is acceleration, so we set a = 0.
3 more steps, each with the reason for it, in the full solution
Final answer
16 m s⁻¹
Where students lose marks
Watch out: t = 3 is only the time. Substitute it back into v_A to get the maximum velocity.
Part (b)
12 more steps, each with the reason for it, in the full solution
Final answer
(i) t = √15/2 ≈ 1.94 s; (ii) 52 m
Where students lose marks
Watch out: show the factorisation in (i). In (ii), mind the signs when combining legs; 42.67 m is a common wrong answer.
Watch every step of this question solved on video (6:59), with the reason behind each step and a box that checks your own answer.
No card. Every past-year question on video, in English and BM.
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