SPM 2023 Add Maths Paper 2, Question 12Solution of Triangles
Solved on video in English and Bahasa Melayu · Form 4, Solution of Triangles · 9:07 video
The question
(Solutions by scale drawing are not accepted.) Diagram 6 shows a model consisting of a vertical wall ABCD and a horizontal floor CDEF, where CDEF is a parallelogram. It is given that AB = 35 cm, AD = 4 cm, ∠DFE = 30° and ∠DFC = 80°.
(a)(i) Calculate the length, in cm, of CF.
Diagram 6: vertical wall ABCD with AB = 35 cm, AD = 4 cm; horizontal parallelogram floor CDEF; ∠DFE = 30°, ∠DFC = 80°; CF = 17.77 cm.
(a)(ii) Calculate the area, in cm², of triangle ACE.
From the model, AE = 18.21 cm.
(b) A pole of length 5 cm is placed obliquely at corner E. A stick is used to join the top of the pole, G, to corner A, such that ∠EAG = 15°. Find the minimum length, in cm, of the stick.
9:07Part (a)(i)
Step 1
In parallelogram CDEF, DC ∥ EF, so ∠FDC = ∠DFE = 30° (alternate angles). Also DC = AB = 35 cm.
Why this step
Parallel sides make alternate angles equal, so the 30° at F is also at D. We need it because it faces CF, the side we want.
3 more steps, each with the reason for it, in the full solution
Final answer
CF = 17.77 cm
Where students lose marks
Watch out: DC is opposite 80° and CF is opposite 30°. Putting the ratio the wrong way round gives a wrong CF.
Part (a)(ii)
7 more steps, each with the reason for it, in the full solution
Final answer
305.38 cm²
Where students lose marks
Watch out: ∠EAC is not 90°. Find it with the cosine rule first, or you get 320.77 cm² instead of 305.38 cm².
Part (b)
5 more steps, each with the reason for it, in the full solution
Final answer
AG = 15.93 cm
Where students lose marks
Watch out: sin ∠AGE = 0.9426 gives two angles, 70.54° and 109.46°. Taking only the acute one misses the shorter stick.
Watch every step of this question solved on video (9:07), with the reason behind each step and a box that checks your own answer.
No card. Every past-year question on video, in English and BM.
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