SPM 2019 Add Maths Paper 2, Question 7Differentiation
Solved on video in English and Bahasa Melayu · 10 marks · Form 5, Differentiation · 7:47 video
The question
A metal solid is formed by combining a cone and a cylinder with common radius, r cm. The total surface area of the solid, A cm², is given by A = 2pi(18/r + r²/3). (a)(i) The solid expands when heated. It is given that the surface area of the solid changes at the rate of 1.4*pi cm² s⁻¹. Find the rate of change of its radius, in cm s⁻¹, when its radius is 6 cm. (a)(ii) Find the approximate change in the surface area of the solid, in terms of pi, when its radius increases from 6 cm to 6.02 cm. (b) If a solid of the same shape is to be formed such that the total surface area is minimum, find the minimum total surface area of the solid, in terms of pi.
[10 marks]
7:47Step 1
A = 2pi(18/r + r²/3) = 36pir⁻¹ + (2pi/3)r².
Why this step
Writing 1/r as r⁻¹ lets us use the power rule on both terms, and helps you keep the minus sign right when differentiating.
7 more steps, each with the reason for it, in the full solution
Final answer
(a)(i) dr/dt = 0.2 cm s⁻¹; (a)(ii) δA ≈ 0.14π cm² (increase); (b) A_min = 18π cm²
Where students lose marks
Watch out: divide dA/dt by dA/dr, mind the minus sign when differentiating 36π r⁻¹, and in (b) substitute r = 3 back into A.
Watch every step of this question solved on video (7:47), with the reason behind each step and a box that checks your own answer.
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