Selangor Trial 2025 Add Maths Paper 2, Question 7Integration
Solved on video in English · Form 5, Integration · 6:14 video
The question
(a) The curve f(x) has a gradient function 5/x² − 2 and passes through the point (15, −1). Determine the function f(x).
(b) Calculate the volume generated, in terms of π, when the region bounded by the curve 2y = 1 − √x, the y-axis and y = −1 is revolved 360° about the y-axis.
6:14Part (a)
Step 1
Integrate the gradient function: f(x) = ∫(5x⁻² − 2) dx = 5·(x⁻¹/(−1)) − 2x + c = −5/x − 2x + c.
Why this step
Going from a gradient back to the curve means integrating. Write 5/x² as 5x⁻², add 1 to the power, then divide by the new power −1.
3 more steps, each with the reason for it, in the full solution
Final answer
f(x) = −5/x − 2x + 88/3
Where students lose marks
Watch out: integrate 5x⁻² to −5/x (add 1 to the power, divide by −1), and never leave out + c.
Part (b)
6 more steps, each with the reason for it, in the full solution
Final answer
V = 24.3π = 243π/10
Where students lose marks
Watch out: upper limit is y = 1/2 (where x = 0); x² = (1 − 2y)⁴; and divide by −2 when integrating.
Watch every step of this question solved on video (6:14), with the reason behind each step and a box that checks your own answer.
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