MRSM Trial 2025 Add Maths Paper 2, Question 2Vectors

Solved on video in English · Form 4, Vectors · 4:53 video

The question

(a)(i)

Diagram 1 shows a regular hexagon ABCDEF. Express vector AC in terms of vectors AB and BC. (All symbols with an arrow denote vectors.)

(a)(ii)

Express vector AC in terms of vectors AF and AD. )

(b)

It is given that PQ = 2a, RS = −a and TU = 2b (all are vectors, and a and b are non-parallel vectors). State the pair of parallel vectors and give your justification.

MRSM Trial 2025 Add Maths Paper 2, Question 2: the question as drawn in Eduly's video4:53

Part (a)(i)

Step 1

Apply the triangle law of vector addition along the path A → B → C.

Why this step

Walk tail to head: AB ends at B, where BC begins, so the direct arrow AC is their sum. Subtracting BC is the common slip.

1 more step, with the reason for it, in the full solution

Final answer

AC = AB + BC

Where students lose marks

Watch out: follow the path A → B → C tail to head, so add AB + BC. Do not subtract BC.

Part (a)(ii)

3 more steps, each with the reason for it, in the full solution

Final answer

AC = AD − AF

Where students lose marks

Watch out: in a regular hexagon CD = AF, and DC = −CD, so AC = AD − AF, not AD + AF.

Part (b)

3 more steps, each with the reason for it, in the full solution

Final answer

PQ and RS are parallel, because PQ = −2 RS

Where students lose marks

Watch out: give the scalar-multiple reason PQ = −2 RS. TU = 2b also has a 2, but b is not parallel to a.

Watch every step of this question solved on video (4:53), with the reason behind each step and a box that checks your own answer.

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